Is sec(x)-tan(x)= 1/(sec(x)) ?

The answer to whether sec(x)-tan(x)= 1/(sec(x)) is False

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prove sec(x)-tan(x)= 1/(sec(x))

prove

sec (x) - tan (x) = \frac{1}{sec ( x )}

False

Solution steps

sec (x) - tan (x) = \frac{1}{sec ( x )}

Show that the two sides are not equal

For

sec (x) - tan (x) = \frac{1}{sec ( x )}

plug in

x = 1

sec (1) - tan (1) = 0.29340 \dots

sec (1) - tan (1)

Refine to a decimal form

= 0.29340 \dots

\frac{1}{sec ( 1 )} = 0.54030 \dots

\frac{1}{sec ( 1 )}

Refine to a decimal form

= 0.54030 \dots

The two sides are not equal

\Rightarrow False

tan^{2} (x) + cot^{2} (x) = sec^{2} (x) csc^{2} (x)

tan^{4} (x) = \frac{( sin ^{4} ( x ) )}{cos ^{4} ( x )}

sin^{2} (π) = 1 - cos^{2} (π)

tan (π + x) = tan (x)

\frac{( cot ( x ) + tan ( x ) )}{cot ( x ) - tan ( x )} = sec (2 x)

Is sec(x)-tan(x)= 1/(sec(x)) ?
The answer to whether sec(x)-tan(x)= 1/(sec(x)) is False