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Popular >

tanh(1)

Solution

tanh (1)

Solution

\frac{e ^{2} - 1}{e ^{2} + 1}

+1

Solution steps

tanh (1)

Use the Hyperbolic identity:

tanh (x) = \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

= \frac{e ^{1} - e ^{- 1}}{e ^{1} + e ^{- 1}}

\frac{e ^{1} - e ^{- 1}}{e ^{1} + e ^{- 1}} = \frac{e ^{2} - 1}{e ^{2} + 1}

= \frac{e ^{2} - 1}{e ^{2} + 1}

Popular Examples

tan (\frac{5 π}{4})

tan (22 5^{\circ})

tan (30 0^{\circ})

cos (- \frac{5 π}{6})

2 tan^{2} (x) - 2 = 0

Frequently Asked Questions (FAQ)

What is the value of tanh(1) ?
The value of tanh(1) is (e^2-1)/(e^2+1)