Is sin(x)-csc(x)=cos^2(x)csc(x) ?

The answer to whether sin(x)-csc(x)=cos^2(x)csc(x) is False

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prove sin(x)-csc(x)=cos^2(x)csc(x)

prove

sin (x) - csc (x) = cos^{2} (x) csc (x)

False

Solution steps

sin (x) - csc (x) = cos^{2} (x) csc (x)

Show that the two sides are not equal

For

sin (x) - csc (x) = cos^{2} (x) csc (x)

plug in

x = 1

sin (1) - csc (1) = - 0.34692 \dots

sin (1) - csc (1)

Refine to a decimal form

= - 0.34692 \dots

cos^{2} (1) csc (1) = 0.34692 \dots

cos^{2} (1) csc (1)

Refine to a decimal form

= 0.34692 \dots

The two sides are not equal

\Rightarrow False

tan^{2} (x) = cos^{2} (tan^{2} (- 1))

\frac{csc ( x ) - sin ( x )}{cot ( x )} = cos (x)

csc (x) sec (x) = 2 csc^{2} (x)

cos^{2} (x) cot^{2} (x) = cot^{2} (x) - cos^{2} (x)

sin^{2} (x) sec^{2} (x) = tan^{2} (x)

Is sin(x)-csc(x)=cos^2(x)csc(x) ?
The answer to whether sin(x)-csc(x)=cos^2(x)csc(x) is False