Is cos(2x)cot(x)=1-cos^2(x) ?

The answer to whether cos(2x)cot(x)=1-cos^2(x) is False

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prove cos(2x)cot(x)=1-cos^2(x)

prove

cos (2 x) cot (x) = 1 - cos^{2} (x)

False

Solution steps

cos (2 x) cot (x) = 1 - cos^{2} (x)

Show that the two sides are not equal

For

cos (2 x) cot (x) = 1 - cos^{2} (x)

plug in

x = 1

cos (2 \cdot 1) cot (1) = - 0.26720 \dots

cos (2 \cdot 1) cot (1)

Refine to a decimal form

= - 0.26720 \dots

1 - cos^{2} (1) = 0.70807 \dots

1 - cos^{2} (1)

Refine to a decimal form

= 0.70807 \dots

The two sides are not equal

\Rightarrow False

\frac{csc ( x ) tan ( x )}{1 + tan ^{2} ( x )} = cos (x)

- sin^{2} (θ) = cos^{2} (θ) - 1

sec (x) + cos (x) = tan (x) sin (x)

\frac{sin ( x ) + tan ( x )}{cos ( x ) + 1} = tan (x)

cos^{2} (2 x) = \frac{1}{2} + \frac{1}{2} cos (4 x)

Is cos(2x)cot(x)=1-cos^2(x) ?
The answer to whether cos(2x)cot(x)=1-cos^2(x) is False