Is sec^2(θ)(1-sin^2(θ))=sec^2(θ) ?

The answer to whether sec^2(θ)(1-sin^2(θ))=sec^2(θ) is False

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prove sec^2(θ)(1-sin^2(θ))=sec^2(θ)

prove

sec^{2} (θ) (1 - sin^{2} (θ)) = sec^{2} (θ)

False

Solution steps

sec^{2} (θ) (1 - sin^{2} (θ)) = sec^{2} (θ)

Show that the two sides are not equal

For

sec^{2} (θ) (1 - sin^{2} (θ)) = sec^{2} (θ)

plug in

θ = 1

sec^{2} (1) (1 - sin^{2} (1)) = 1

sec^{2} (1) (1 - sin^{2} (1))

Refine to a decimal form

= 1

sec^{2} (1) = 3.42551 \dots

sec^{2} (1)

Refine to a decimal form

= 3.42551 \dots

The two sides are not equal

\Rightarrow False

cos (x - 9 0^{\circ}) = sin (x)

\frac{1 + sec ( B )}{tan ( B ) + sin ( B )} = csc (B)

\frac{sin ( θ )}{cos ^{2} ( θ )} = tan (θ) sec (θ)

\frac{sec ( v ) - cos ( v )}{sec ( v )} = sin^{2} (v)

\frac{cos ( 2 θ )}{sin ^{2} ( θ )} = 2 cos^{2} (θ)

Is sec^2(θ)(1-sin^2(θ))=sec^2(θ) ?
The answer to whether sec^2(θ)(1-sin^2(θ))=sec^2(θ) is False