Is 1+cot^2(z)=csc^2(z) ?

The answer to whether 1+cot^2(z)=csc^2(z) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 1+cot^2(z)=csc^2(z)

prove

1 + cot^{2} (z) = csc^{2} (z)

True

Solution steps

1 + cot^{2} (z) = csc^{2} (z)

Use the Pythagorean identity:

1 + cot^{2} (x) = csc^{2} (x)

\Rightarrow True

csc (x) - 1 = \frac{2 sin ( x )}{sin ( x )}

2 sin^{2} (θ) - cos (2 θ) = 1

\frac{1}{csc ( + 1 )} + \frac{1}{sin ( x ) + 1} = 1

\frac{( tan ^{2} ( t ) )}{sec ( t )} = sec (t) - cos (t)

\frac{tan ( a ) sin ( a )}{sec ( a ) - 1} = 1 + cos (a)