Is (1+cos(2θ))(1-cos(2θ))=sin^2(2θ) ?

The answer to whether (1+cos(2θ))(1-cos(2θ))=sin^2(2θ) is True

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prove (1+cos(2θ))(1-cos(2θ))=sin^2(2θ)

prove

(1 + cos (2 θ)) (1 - cos (2 θ)) = sin^{2} (2 θ)

True

Solution steps

(1 + cos (2 θ)) (1 - cos (2 θ)) = sin^{2} (2 θ)

(1 + cos (x)) (1 - cos (x)) = sin^{2} (x)

\Rightarrow True

sin (x) - cos (x) = 0

sin (2 θ) + cos (2 θ) = 2 sin (θ) cos (θ) + 2 cos^{2} (θ) - 1

\frac{tan ^{4} ( x ) - 1}{tan ^{2} ( x ) - 1} = sec^{2} (x)

cos (27 0^{\circ} - θ) = - sin (θ)

1 - cos^{2} (x) tan^{2} (x) = cos^{2} (x)

Is (1+cos(2θ))(1-cos(2θ))=sin^2(2θ) ?
The answer to whether (1+cos(2θ))(1-cos(2θ))=sin^2(2θ) is True