Is csc(θ)+sec(θ)=tan(θ)+1 ?

The answer to whether csc(θ)+sec(θ)=tan(θ)+1 is False

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prove csc(θ)+sec(θ)=tan(θ)+1

prove

csc (θ) + sec (θ) = tan (θ) + 1

False

Solution steps

csc (θ) + sec (θ) = tan (θ) + 1

Show that the two sides are not equal

\Rightarrow False

\frac{cos ( t ) + 1}{sin ( t ) + sec ( t )} = \frac{tan ( t )}{sec ( t ) - 1}

\frac{cot ( θ ) - tan ( θ )}{cot ( θ ) + tan ( θ )} = cos (2 θ)

cos^{2} (2 x) + 4 sin^{2} (x) cos^{2} (x) = 1

cos (x) (sec (x) - 1) = 1 - cos (x)

3 sec^{2} (33 0^{\circ}) tan (33 0^{\circ}) = 4 tan (33 0^{\circ})

Is csc(θ)+sec(θ)=tan(θ)+1 ?
The answer to whether csc(θ)+sec(θ)=tan(θ)+1 is False