Is (1-cos(θ^2))(1+cot(θ^2))=1 ?

The answer to whether (1-cos(θ^2))(1+cot(θ^2))=1 is False

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prove (1-cos(θ^2))(1+cot(θ^2))=1

prove

(1 - cos (θ^{2})) (1 + cot (θ^{2})) = 1

False

Solution steps

(1 - cos (θ^{2})) (1 + cot (θ^{2})) = 1

Show that the two sides are not equal

\Rightarrow False

cos (2 x) = \frac{2 - sec ^{2} ( x )}{sec ^{2} ( x )}

cot (y) = \frac{sin ( 2 y )}{1 - cos ( 2 y )}

1 + \frac{1}{tan ^{2} ( α )} = \frac{1}{sin ^{2} ( α )}

tan (x) + sec (x) = \frac{sin ( x ) + 1}{cos ( x )}

sin (x) - tan (x) = \frac{1}{sec ( x ) tan ( x )}

Is (1-cos(θ^2))(1+cot(θ^2))=1 ?
The answer to whether (1-cos(θ^2))(1+cot(θ^2))=1 is False