Is tan(x)+sec(x)=(sin(x)+1)/(cos(x)) ?

The answer to whether tan(x)+sec(x)=(sin(x)+1)/(cos(x)) is True

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prove tan(x)+sec(x)=(sin(x)+1)/(cos(x))

prove

tan (x) + sec (x) = \frac{sin ( x ) + 1}{cos ( x )}

True

Solution steps

tan (x) + sec (x) = \frac{sin ( x ) + 1}{cos ( x )}

Manipulating left side

tan (x) + sec (x)

Express with sin, cos

= \frac{1 + sin ( x )}{cos ( x )}

= \frac{sin ( x ) + 1}{cos ( x )}

We showed that the two sides could take the same form

\Rightarrow True

sin (x) - tan (x) = \frac{1}{sec ( x ) tan ( x )}

\frac{sin ( t ) cos ( t )}{tan ( t )} = cos^{2} (t)

\frac{tan ( x )}{1 - cot ( x )} + \frac{cot ( x )}{1 - tan ( x )} = 1 + sec (x) sin (x)

sec (θ) (sec (θ) - cos (θ)) = tan^{2} (θ)

cot^{2} (θ) = \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

Is tan(x)+sec(x)=(sin(x)+1)/(cos(x)) ?
The answer to whether tan(x)+sec(x)=(sin(x)+1)/(cos(x)) is True