Is (sin^2(x)-1)=-cos^2(x) ?

The answer to whether (sin^2(x)-1)=-cos^2(x) is True

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prove (sin^2(x)-1)=-cos^2(x)

prove

(sin^{2} (x) - 1) = - cos^{2} (x)

True

Solution steps

sin^{2} (x) - 1 = - cos^{2} (x)

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

\Rightarrow True

cos (- \frac{x π}{3}) = cos (\frac{x π}{3})

1 + sin (x) = cos (x)

sin (2 y) = \frac{2 tan ( y )}{1 + tan ^{2} ( y )}

sec^{2} (β) + sec^{2} (β) = \frac{2}{cos ^{2} ( β )}

3 csc (x) - cot (x) = \frac{3 - cos ( x )}{sin ( x )}

Is (sin^2(x)-1)=-cos^2(x) ?
The answer to whether (sin^2(x)-1)=-cos^2(x) is True