Is sec^2(β)+sec^2(β)= 2/(cos^2(β)) ?

The answer to whether sec^2(β)+sec^2(β)= 2/(cos^2(β)) is True

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prove sec^2(β)+sec^2(β)= 2/(cos^2(β))

prove

sec^{2} (β) + sec^{2} (β) = \frac{2}{cos ^{2} ( β )}

True

Solution steps

sec^{2} (β) + sec^{2} (β) = \frac{2}{cos ^{2} ( β )}

Manipulating left side

sec^{2} (β) + sec^{2} (β)

Express with sin, cos

= \frac{2}{cos ^{2} ( β )}

We showed that the two sides could take the same form

\Rightarrow True

3 csc (x) - cot (x) = \frac{3 - cos ( x )}{sin ( x )}

\frac{1}{1 - sin ( θ )} = sec^{2} (θ) + sec (θ) tan (θ)

\frac{1}{tan ^{2} ( θ )} - cos (θ) = cos^{2} (θ)

2 sin (x) = tan (x)

1 \cdot sin (t) + (- 1) \cdot cos (t - \frac{π}{2}) = 0

Is sec^2(β)+sec^2(β)= 2/(cos^2(β)) ?
The answer to whether sec^2(β)+sec^2(β)= 2/(cos^2(β)) is True