Is sin(θ)csc(θ)+cot(θ)sin(θ)=1+cos(θ) ?

The answer to whether sin(θ)csc(θ)+cot(θ)sin(θ)=1+cos(θ) is True

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prove sin(θ)csc(θ)+cot(θ)sin(θ)=1+cos(θ)

prove

sin (θ) csc (θ) + cot (θ) sin (θ) = 1 + cos (θ)

True

Solution steps

sin (θ) csc (θ) + cot (θ) sin (θ) = 1 + cos (θ)

Manipulating left side

sin (θ) csc (θ) + cot (θ) sin (θ)

Express with sin, cos

= 1 + cos (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan (x) cot (x) = csc (x) sec (x)

sin^{2} (θ) = 1 + cos^{2} (θ)

csc (θ) + cos^{2} (θ) = csc (θ)

sin (\frac{π}{2}) = \frac{4}{2}

sec (\frac{π}{4} + a) sec (\frac{π}{4} - a) = 2 sec (2 a)

Is sin(θ)csc(θ)+cot(θ)sin(θ)=1+cos(θ) ?
The answer to whether sin(θ)csc(θ)+cot(θ)sin(θ)=1+cos(θ) is True