Is csc(θ)+cos^2(θ)=csc(θ) ?

The answer to whether csc(θ)+cos^2(θ)=csc(θ) is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove csc(θ)+cos^2(θ)=csc(θ)

prove

csc (θ) + cos^{2} (θ) = csc (θ)

False

Solution steps

csc (θ) + cos^{2} (θ) = csc (θ)

Show that the two sides are not equal

\Rightarrow False

sin (\frac{π}{2}) = \frac{4}{2}

sec (\frac{π}{4} + a) sec (\frac{π}{4} - a) = 2 sec (2 a)

sin^{4} (x) = sec^{2} (x) tan^{2} (x) + sec^{2} (x)

(1 + cos (x)) (1 - sec (x)) = - 1

cot^{2} (\frac{v}{2}) = \frac{( sec ( v ) + 1 )}{( sec ( v ) - 1 )}

Is csc(θ)+cos^2(θ)=csc(θ) ?
The answer to whether csc(θ)+cos^2(θ)=csc(θ) is False