Is (cos(x)+sin(x))^2=1+2cos(x)sin(x) ?

The answer to whether (cos(x)+sin(x))^2=1+2cos(x)sin(x) is True

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prove (cos(x)+sin(x))^2=1+2cos(x)sin(x)

prove

(cos (x) + sin (x))^{2} = 1 + 2 cos (x) sin (x)

True

Solution steps

(cos (x) + sin (x))^{2} = 1 + 2 cos (x) sin (x)

Manipulating left side

(cos (x) + sin (x))^{2}

Expand

(cos (x) + sin (x))^{2} : cos^{2} (x) + 2 cos (x) sin (x) + sin^{2} (x)

(cos (x) + sin (x))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = cos (x), b = sin (x)

= cos^{2} (x) + 2 cos (x) sin (x) + sin^{2} (x)

= cos^{2} (x) + sin^{2} (x) + 2 cos (x) sin (x)

Rewrite using trig identities

cos^{2} (x) + sin^{2} (x) + 2 cos (x) sin (x)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= 1 + 2 cos (x) sin (x)

= 1 + 2 cos (x) sin (x)

We showed that the two sides could take the same form

\Rightarrow True

tan (\frac{5 π}{3}) = - 3

sin (A) = \frac{3}{5}

cos (2 x) = cos (- 2 x)

tan (x) \cdot csc (x) = sec (x)

tan (θ) sin (θ) = 2 sin^{2} (θ)

Is (cos(x)+sin(x))^2=1+2cos(x)sin(x) ?
The answer to whether (cos(x)+sin(x))^2=1+2cos(x)sin(x) is True