Is sin^2(pi/2)=1-cos^2(pi/2) ?

The answer to whether sin^2(pi/2)=1-cos^2(pi/2) is True

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prove sin^2(pi/2)=1-cos^2(pi/2)

prove

sin^{2} (\frac{π}{2}) = 1 - cos^{2} (\frac{π}{2})

True

Solution steps

sin^{2} (\frac{π}{2}) = 1 - cos^{2} (\frac{π}{2})

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

\Rightarrow True

cot (θ) - tan (θ) = \frac{2 cos ( 2 θ )}{sin ( 2 θ )}

\frac{sec ^{2} ( x )}{tan ( x )} = 2 csc (2 x)

tan (- u) \cdot sin (- u) + cos (- u) = sec (u)

\frac{2 sin ^{2} ( x )}{sin ( 2 x )} = \frac{1}{cot ( x )}

csc (x) (csc (x) + sin (- x)) = cot^{2} (x)

Is sin^2(pi/2)=1-cos^2(pi/2) ?
The answer to whether sin^2(pi/2)=1-cos^2(pi/2) is True