Is tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) ?

The answer to whether tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) is False

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prove tan^2(a)+sin^2(a)=tan^2(a)sin^2(a)

prove

tan^{2} (a) + sin^{2} (a) = tan^{2} (a) sin^{2} (a)

False

Solution steps

tan^{2} (a) + sin^{2} (a) = tan^{2} (a) sin^{2} (a)

Show that the two sides are not equal

For

tan^{2} (a) + sin^{2} (a) = tan^{2} (a) sin^{2} (a)

plug in

a = 1

tan^{2} (1) + sin^{2} (1) = 3.13359 \dots

tan^{2} (1) + sin^{2} (1)

Refine to a decimal form

= 3.13359 \dots

tan^{2} (1) sin^{2} (1) = 1.71744 \dots

tan^{2} (1) sin^{2} (1)

Refine to a decimal form

= 1.71744 \dots

The two sides are not equal

\Rightarrow False

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\frac{1}{1 - sin ( x )} = - \frac{1}{sin ( x )}

tan (- a) = - tan (a)

\frac{tan ( y ) + cos ( y )}{1 + sin ( y )} = sec (y)

sin^{2} (x) + cos (2 x) = 1 - sin^{2} (x)

Is tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) ?
The answer to whether tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) is False