Is (tan(y)+cos(y))/(1+sin(y))=sec(y) ?

The answer to whether (tan(y)+cos(y))/(1+sin(y))=sec(y) is False

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prove (tan(y)+cos(y))/(1+sin(y))=sec(y)

prove

\frac{tan ( y ) + cos ( y )}{1 + sin ( y )} = sec (y)

False

Solution steps

\frac{tan ( y ) + cos ( y )}{1 + sin ( y )} = sec (y)

Show that the two sides are not equal

For

\frac{tan ( y ) + cos ( y )}{1 + sin ( y )} = sec (y)

plug in

y = 1

\frac{tan ( 1 ) + cos ( 1 )}{1 + sin ( 1 )} = 1.13914 \dots

\frac{tan ( 1 ) + cos ( 1 )}{1 + sin ( 1 )}

Refine to a decimal form

= 1.13914 \dots

sec (1) = 1.85081 \dots

sec (1)

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

sin^{2} (x) + cos (2 x) = 1 - sin^{2} (x)

cos (4 5^{\circ}) = \frac{sin ( 2 \cdot 4 5 ^{\circ} )}{2 \cdot sin ( 4 5 ^{\circ} )}

4 sin (3 x) cos (4 x) = 2 sin (7 x) - 2 sin (x)

sec^{2} (x) = \frac{sec ( x )}{cos ( x )}

cot (θ) \cdot sin (θ) = cos (θ)

Is (tan(y)+cos(y))/(1+sin(y))=sec(y) ?
The answer to whether (tan(y)+cos(y))/(1+sin(y))=sec(y) is False