Is sec^2(θ)+csc(θ)=-sec^2(θ)csc(θ) ?

The answer to whether sec^2(θ)+csc(θ)=-sec^2(θ)csc(θ) is False

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prove sec^2(θ)+csc(θ)=-sec^2(θ)csc(θ)

prove

sec^{2} (θ) + csc (θ) = - sec^{2} (θ) csc (θ)

False

Solution steps

sec^{2} (θ) + csc (θ) = - sec^{2} (θ) csc (θ)

Show that the two sides are not equal

For

sec^{2} (θ) + csc (θ) = - sec^{2} (θ) csc (θ)

plug in

θ = 1

sec^{2} (1) + csc (1) = 4.61391 \dots

sec^{2} (1) + csc (1)

Refine to a decimal form

= 4.61391 \dots

- sec^{2} (1) csc (1) = - 4.07086 \dots

- sec^{2} (1) csc (1)

Refine to a decimal form

= - 4.07086 \dots

The two sides are not equal

\Rightarrow False

tan (5 x) = tan (3 x) sec (2 x) - tan (3 x)

1 - 2 cos^{2} (x) = sin^{2} (x) - cos^{2} (x)

sin (4 0^{\circ}) = 2 \cdot sin (2 0^{\circ}) \cdot cos (2 0^{\circ})

9 sec (y) cos (y) = 9

- sin (- x) = sin (x)

Is sec^2(θ)+csc(θ)=-sec^2(θ)csc(θ) ?
The answer to whether sec^2(θ)+csc(θ)=-sec^2(θ)csc(θ) is False