Is sqrt(81-9(3sin(x))^2)=1 ?

The answer to whether sqrt(81-9(3sin(x))^2)=1 is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove sqrt(81-9(3sin(x))^2)=1

prove

81 - 9 (3 sin (x))^{2} = 1

False

Solution steps

81 - 9 (3 sin (x))^{2} = 1

Show that the two sides are not equal

For

81 - 9 (3 sin (x))^{2} = 1

plug in

x = 0

81 - 9 (3 sin (0))^{2} = 9

81 - 9 (3 sin (0))^{2}

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 81 - 9 (3 \cdot 0)^{2}

Simplify

81 - 9 (3 \cdot 0)^{2} : 9

81 - 9 (3 \cdot 0)^{2}

9 (3 \cdot 0)^{2} = 0

9 (3 \cdot 0)^{2}

(3 \cdot 0)^{2} = 0

(3 \cdot 0)^{2}

Apply rule

0 \cdot a = 0

= 0^{2}

Apply rule

0^{a} = 0

= 0

= 9 \cdot 0

Apply rule

0 \cdot a = 0

= 0

= 81 - 0

Subtract the numbers:

81 - 0 = 81

= 81

Factor the number:

81 = 9^{2}

= 9^{2}

Apply radical rule:

9^{2} = 9

= 9

= 9

The two sides are not equal

\Rightarrow False

\frac{1 + sec ( x )}{csc ( x )} = sin (x) + tan (x)

\frac{tan ^{2} ( t )}{sec ( t )} = sec (t) - cot (t)

81 - 9 (3 sin (x))^{2} = 9 cos (x)

25 tan^{2} (5 x) + 25 = 25 + (5 tan (5 x))^{2}

(1 + tan (a)) \cdot (1 - tan (a)) = 2 - sec^{2} (a)

Is sqrt(81-9(3sin(x))^2)=1 ?
The answer to whether sqrt(81-9(3sin(x))^2)=1 is False