Is prove-sin(θ)=-sin(-θ) ?

The answer to whether prove-sin(θ)=-sin(-θ) is False

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prove-sin(θ)=-sin(-θ)

prove

- sin (θ) = - sin (- θ)

False

Solution steps

- sin (θ) = - sin (- θ)

Show that the two sides are not equal

For

- sin (θ) = - sin (- θ)

plug in

θ = 1

- sin (1) = - 0.84147 \dots

- sin (1)

Refine to a decimal form

= - 0.84147 \dots

- sin (- 1) = sin (1) (Decimal : 0.84147 \dots)

- sin (- 1)

Use the following property:

sin (- x) = - sin (x)

sin (- 1) = - sin (1)

= - (- sin (1))

= sin (1)

The two sides are not equal

\Rightarrow False

- 8 cos (2 x) - (0) (2 cos (2 x)) = - 8 cos (2 x)

sec^{2} (x) cot^{2} (x) = 1 + cot^{2} (x)

cos (2 B) = \frac{1 - tan ^{2} ( B )}{1 + tan ^{2} ( B )}

sec (u) cos (u) - cos^{2} (u) = sin^{2} (u)

\frac{1 + sec ( x )}{1 + cos ( x )} = sec (x)