Is cos(3x)=cos(x^3)-3sin(x^2) ?

The answer to whether cos(3x)=cos(x^3)-3sin(x^2) is False

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prove cos(3x)=cos(x^3)-3sin(x^2)

prove

cos (3 x) = cos (x^{3}) - 3 sin (x^{2})

False

Solution steps

cos (3 x) = cos (x^{3}) - 3 sin (x^{2})

Show that the two sides are not equal

For

cos (3 x) = cos (x^{3}) - 3 sin (x^{2})

plug in

x = 1

cos (3 \cdot 1) = - 0.98999 \dots

cos (3 \cdot 1)

Refine to a decimal form

= - 0.98999 \dots

cos (1^{3}) - 3 sin (1^{2}) = - 1.98411 \dots

cos (1^{3}) - 3 sin (1^{2})

Refine to a decimal form

= - 1.98411 \dots

The two sides are not equal

\Rightarrow False

tan (B) + cot (B) = csc (B) sec (B)

4 cos (x + y) + 4 cos (x - y) = 8 cos (x) cos (y)

2 cos (x) sec^{2} (x) = \frac{2}{cos ( x )}

\frac{( sin ( t ) + cos ( t ) ) ^{2}}{sin ( t ) cos ( t )} = 2 + sec^{2} (t) (csc^{2} (t))

sec (x) + cos (x) = 1 + cos^{2} (x)

Is cos(3x)=cos(x^3)-3sin(x^2) ?
The answer to whether cos(3x)=cos(x^3)-3sin(x^2) is False