Is sin^2(x)*sec(x)=tan^2(x) ?

The answer to whether sin^2(x)*sec(x)=tan^2(x) is False

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prove sin^2(x)*sec(x)=tan^2(x)

prove

sin^{2} (x) \cdot sec (x) = tan^{2} (x)

False

Solution steps

sin^{2} (x) sec (x) = tan^{2} (x)

Show that the two sides are not equal

For

sin^{2} (x) sec (x) = tan^{2} (x)

plug in

x = 1

sin^{2} (1) sec (1) = 1.31051 \dots

sin^{2} (1) sec (1)

Refine to a decimal form

= 1.31051 \dots

tan^{2} (1) = 2.42551 \dots

tan^{2} (1)

Refine to a decimal form

= 2.42551 \dots

The two sides are not equal

\Rightarrow False

1 + 2 sin (x) cos (x) = (sin (x) + cos (x))^{2}

sin (2 x) = 2 cos (x)

sec (β) sin (β) cot (β) = 1

1 - sin^{2} (θ) + sin^{4} (θ) = cos^{4} (θ)

sec (x) - tan (x) = \frac{cos ^{2} ( x )}{sin ( x )}

Is sin^2(x)*sec(x)=tan^2(x) ?
The answer to whether sin^2(x)*sec(x)=tan^2(x) is False