Is (1+sin(x))/(cos(x)tan(x)-1)=-1 ?

The answer to whether (1+sin(x))/(cos(x)tan(x)-1)=-1 is False

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prove (1+sin(x))/(cos(x)tan(x)-1)=-1

prove

\frac{1 + sin ( x )}{cos ( x ) tan ( x ) - 1} = - 1

False

Solution steps

\frac{1 + sin ( x )}{cos ( x ) tan ( x ) - 1} = - 1

Show that the two sides are not equal

For

\frac{1 + sin ( x )}{cos ( x ) tan ( x ) - 1} = - 1

plug in

x = 1

\frac{1 + sin ( 1 )}{cos ( 1 ) tan ( 1 ) - 1} = - 11.61598 \dots

\frac{1 + sin ( 1 )}{cos ( 1 ) tan ( 1 ) - 1}

Refine to a decimal form

= - 11.61598 \dots

The two sides are not equal

\Rightarrow False

\frac{sin ( x ) sec ( x )}{tan ( x )} = 1

cot (x) + 5 = 5 + csc (x) \cdot cos (x)

csc (θ) = cos (θ) cot (θ) + sin^{2} (θ) csc (θ)

cos (y) csc (y) = cot (y)

\frac{tan ( a )}{sin ( a )} - sec (a) = 0

Is (1+sin(x))/(cos(x)tan(x)-1)=-1 ?
The answer to whether (1+sin(x))/(cos(x)tan(x)-1)=-1 is False