Is (sin(x)sec(x))/(tan(x))=1 ?

The answer to whether (sin(x)sec(x))/(tan(x))=1 is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove (sin(x)sec(x))/(tan(x))=1

prove

\frac{sin ( x ) sec ( x )}{tan ( x )} = 1

True

Solution steps

\frac{sin ( x ) sec ( x )}{tan ( x )} = 1

Manipulating left side

\frac{sin ( x ) sec ( x )}{tan ( x )}

Express with sin, cos

\frac{sec ( x ) sin ( x )}{tan ( x )}

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{\frac{1}{c o s ( x )} sin ( x )}{tan ( x )}

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{\frac{1}{c o s ( x )} sin ( x )}{\frac{s i n ( x )}{c o s ( x )}}

\frac{\frac{1}{c o s ( x )} sin ( x )}{\frac{s i n ( x )}{c o s ( x )}} = 1

\frac{\frac{1}{c o s ( x )} sin ( x )}{\frac{s i n ( x )}{c o s ( x )}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{\frac{1}{c o s ( x )} sin ( x ) cos ( x )}{sin ( x )}

Multiply

\frac{1}{cos ( x )} sin (x) cos (x) : sin (x)

\frac{1}{cos ( x )} sin (x) cos (x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( x ) cos ( x )}{cos ( x )}

Cancel the common factor:

cos (x)

= 1 \cdot sin (x)

Multiply:

1 \cdot sin (x) = sin (x)

= sin (x)

= \frac{sin ( x )}{sin ( x )}

Apply rule

\frac{a}{a} = 1

= 1

= 1

= 1

We showed that the two sides could take the same form

\Rightarrow True

cot (x) + 5 = 5 + csc (x) \cdot cos (x)

csc (θ) = cos (θ) cot (θ) + sin^{2} (θ) csc (θ)

cos (y) csc (y) = cot (y)

\frac{tan ( a )}{sin ( a )} - sec (a) = 0

\frac{1}{cot ( θ )} = \frac{tan ( θ )}{sin ( θ )}

Is (sin(x)sec(x))/(tan(x))=1 ?
The answer to whether (sin(x)sec(x))/(tan(x))=1 is True