Is 1/(cot(θ))=(tan(θ))/(sin(θ)) ?

The answer to whether 1/(cot(θ))=(tan(θ))/(sin(θ)) is False

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prove 1/(cot(θ))=(tan(θ))/(sin(θ))

prove

\frac{1}{cot ( θ )} = \frac{tan ( θ )}{sin ( θ )}

False

Solution steps

\frac{1}{cot ( θ )} = \frac{tan ( θ )}{sin ( θ )}

Show that the two sides are not equal

For

\frac{1}{cot ( θ )} = \frac{tan ( θ )}{sin ( θ )}

plug in

θ = 1

\frac{1}{cot ( 1 )} = 1.55740 \dots

\frac{1}{cot ( 1 )}

Refine to a decimal form

= 1.55740 \dots

\frac{tan ( 1 )}{sin ( 1 )} = 1.85081 \dots

\frac{tan ( 1 )}{sin ( 1 )}

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

\frac{1 + sin ( θ )}{cos ( θ )} = sec (θ) + cot (θ)

2 cos (θ) = \frac{2}{sec ( θ )}

(1 + sin (θ)) (1 - sin (θ)) = cos^{2} (x)

sin^{2} (θ) = csc (θ)

\frac{1 - cot ( a )}{csc ( a )} = sin (a) - cos (a)

Is 1/(cot(θ))=(tan(θ))/(sin(θ)) ?
The answer to whether 1/(cot(θ))=(tan(θ))/(sin(θ)) is False