Is sin^2(θ)=csc(θ) ?

The answer to whether sin^2(θ)=csc(θ) is False

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prove sin^2(θ)=csc(θ)

prove

sin^{2} (θ) = csc (θ)

False

Solution steps

sin^{2} (θ) = csc (θ)

Show that the two sides are not equal

For

sin^{2} (θ) = csc (θ)

plug in

θ = 1

sin^{2} (1) = 0.70807 \dots

sin^{2} (1)

Refine to a decimal form

= 0.70807 \dots

csc (1) = 1.18839 \dots

csc (1)

Refine to a decimal form

= 1.18839 \dots

The two sides are not equal

\Rightarrow False

\frac{1 - cot ( a )}{csc ( a )} = sin (a) - cos (a)

\frac{1}{tan ^{2} ( x ) + 1} + \frac{1}{cot ^{2} ( x ) + 1} = 1

2 sin (x^{2}) - sin (x) - 3 = 0

sin (9 0^{\circ} - θ) = cos (θ)

1 + (cot (x))^{2} = (csc (x))^{2}