Is 2sin(x^2)-sin(x)-3=0 ?

The answer to whether 2sin(x^2)-sin(x)-3=0 is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 2sin(x^2)-sin(x)-3=0

prove

2 sin (x^{2}) - sin (x) - 3 = 0

False

Solution steps

2 sin (x^{2}) - sin (x) - 3 = 0

Show that the two sides are not equal

For

2 sin (x^{2}) - sin (x) - 3 = 0

plug in

x = 0

2 sin (0^{2}) - sin (0) - 3 = - 3

2 sin (0^{2}) - sin (0) - 3

Simplify

= sin (0) - 3

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0 - 3

Simplify

= - 3

The two sides are not equal

\Rightarrow False

sin (9 0^{\circ} - θ) = cos (θ)

1 + (cot (x))^{2} = (csc (x))^{2}

cos (a) sec (a) = 1

cos^{2} (x) = \frac{csc ^{2} ( x ) - 1}{csc ^{2} ( x )}

\frac{1 - cos ( x )}{sin ( x )} = tan (x)