Is cos^2(θ)-sin^2(θ)=1-tan^2(θ) ?

The answer to whether cos^2(θ)-sin^2(θ)=1-tan^2(θ) is False

Popular >

prove cos^2(θ)-sin^2(θ)=1-tan^2(θ)

prove

cos^{2} (θ) - sin^{2} (θ) = 1 - tan^{2} (θ)

False

Solution steps

cos^{2} (θ) - sin^{2} (θ) = 1 - tan^{2} (θ)

Show that the two sides are not equal

For

cos^{2} (θ) - sin^{2} (θ) = 1 - tan^{2} (θ)

plug in

θ = 1

cos^{2} (1) - sin^{2} (1) = - 0.41614 \dots

cos^{2} (1) - sin^{2} (1)

Refine to a decimal form

= - 0.41614 \dots

1 - tan^{2} (1) = - 1.42551 \dots

1 - tan^{2} (1)

Refine to a decimal form

= - 1.42551 \dots

The two sides are not equal

\Rightarrow False

tan (6 x) sec (3 x) = 2 sin (3 x) sec (6 x)

sec (θ) (cos (θ) + cot (θ)) = csc (θ)

cos (θ) = \frac{11}{6}

1 - sin^{2} (\frac{x}{4}) = cos (\frac{x}{2})

\frac{csc ( θ ) + sec ( θ )}{csc ( θ )} = csc (θ)

Is cos^2(θ)-sin^2(θ)=1-tan^2(θ) ?
The answer to whether cos^2(θ)-sin^2(θ)=1-tan^2(θ) is False