Is (1-csc(x))/(sec(x))=cot(x)cos(x) ?

The answer to whether (1-csc(x))/(sec(x))=cot(x)cos(x) is False

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prove (1-csc(x))/(sec(x))=cot(x)cos(x)

prove

\frac{1 - csc ( x )}{sec ( x )} = cot (x) cos (x)

False

Solution steps

\frac{1 - csc ( x )}{sec ( x )} = cot (x) cos (x)

Show that the two sides are not equal

For

\frac{1 - csc ( x )}{sec ( x )} = cot (x) cos (x)

plug in

x = 1

\frac{1 - csc ( 1 )}{sec ( 1 )} = - 0.10179 \dots

\frac{1 - csc ( 1 )}{sec ( 1 )}

Refine to a decimal form

= - 0.10179 \dots

cot (1) cos (1) = 0.34692 \dots

cot (1) cos (1)

Refine to a decimal form

= 0.34692 \dots

The two sides are not equal

\Rightarrow False

cos (9 0^{\circ} + 3 0^{\circ}) = cos (12 0^{\circ})

sin (θ) cos (θ) = sin (θ)

(1 - cos (x)) - cos (y) = sin (x + y)

1 - sin (x) = cos^{2} (x)

csc (θ) \cdot sec (θ) - cot (θ) = tan (θ)

Is (1-csc(x))/(sec(x))=cot(x)cos(x) ?
The answer to whether (1-csc(x))/(sec(x))=cot(x)cos(x) is False