Is 1-sin^2(x)=-cos(x) ?

The answer to whether 1-sin^2(x)=-cos(x) is False

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prove 1-sin^2(x)=-cos(x)

prove

1 - sin^{2} (x) = - cos (x)

False

Solution steps

1 - sin^{2} (x) = - cos (x)

Show that the two sides are not equal

\Rightarrow False

tan^{- 3} (x) = (tan (x))^{- 3}

\frac{1}{- 6 csc ^{2} ( 6 x - 1 )} = - \frac{sin ^{2} ( 6 x - 1 )}{6}

sin (x) - tan (x) = \frac{1}{sec ( x ) + tan ( x )}

csc (2 x) = \frac{- 2 3}{3}

\frac{sec ( θ ) - 1}{sec ( θ ) + 1} = \frac{tan ( θ ) - sin ( θ )}{tan ( θ ) + sin ( θ )}