Is tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) ?

The answer to whether tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) is False

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prove tan^2(x)sin^2(x)=tan^2(x)+sin^2(x)

prove

tan^{2} (x) sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

False

Solution steps

tan^{2} (x) sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

Show that the two sides are not equal

For

tan^{2} (x) sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

plug in

x = 1

tan^{2} (1) sin^{2} (1) = 1.71744 \dots

tan^{2} (1) sin^{2} (1)

Refine to a decimal form

= 1.71744 \dots

tan^{2} (1) + sin^{2} (1) = 3.13359 \dots

tan^{2} (1) + sin^{2} (1)

Refine to a decimal form

= 3.13359 \dots

The two sides are not equal

\Rightarrow False

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Is tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) ?
The answer to whether tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) is False