Is tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) ?

The answer to whether tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) is False

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prove tan^2(x)sin^2(x)=tan^2(x)+sin^2(x)

prove

tan^{2} (x) sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

False

Solution steps

tan^{2} (x) sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

Show that the two sides are not equal

\Rightarrow False

cos (- \frac{π}{6}) = sin (- \frac{π}{6} + \frac{π}{2})

3 sin (2 x - 15) = cos (2 x - 15)

cos^{2} (x) - 2 sin^{2} (x) = 3 cos^{2} (x) - 2

sin (x) sec (x) cot (x) = cot (x)

sin (\frac{7 π}{4}) = sin (\frac{- π}{4})

Is tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) ?
The answer to whether tan^2(x)sin^2(x)=tan^2(x)+sin^2(x) is False