Is sin(x)sec(x)cot(x)=cot(x) ?

The answer to whether sin(x)sec(x)cot(x)=cot(x) is False

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prove sin(x)sec(x)cot(x)=cot(x)

prove

sin (x) sec (x) cot (x) = cot (x)

False

Solution steps

sin (x) sec (x) cot (x) = cot (x)

Show that the two sides are not equal

For

sin (x) sec (x) cot (x) = cot (x)

plug in

x = 1

sin (1) sec (1) cot (1) = sin (1) sec (1) cot (1) (Decimal : 1)

sin (1) sec (1) cot (1)

Rewrite using trig identities:

sec (1) sin (1) = tan (1)

sec (1) sin (1)

Express with sin, cos

sec (1) sin (1)

Use the basic trigonometric identity:

sec (1) = \frac{1}{cos ( 1 )}

= \frac{1}{cos ( 1 )} sin (1)

Simplify

\frac{1}{cos ( 1 )} sin (1) : \frac{sin ( 1 )}{cos ( 1 )}

\frac{1}{cos ( 1 )} sin (1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 sin ( 1 )}{cos ( 1 )}

Multiply:

1 \cdot sin (1) = sin (1)

= \frac{sin ( 1 )}{cos ( 1 )}

= \frac{sin ( 1 )}{cos ( 1 )}

= \frac{sin ( 1 )}{cos ( 1 )}

Use the basic trigonometric identity:

\frac{sin ( 1 )}{cos ( 1 )} = tan (1)

= tan (1)

= tan (1)

= sin (1) sec (1) cot (1)

cot (1) = 0.64209 \dots

cot (1)

Refine to a decimal form

= 0.64209 \dots

The two sides are not equal

\Rightarrow False

sin (\frac{7 π}{4}) = sin (\frac{- π}{4})

cos (π - θ) = cos (θ)

tan (x) = \frac{4}{5}

tan (2 x) = \frac{2 tan ( x )}{( 1 - tan ^{2} ( x ) )}

\frac{cot ^{2} ( t )}{cos ( t )} = cot (t) csc (t)

Is sin(x)sec(x)cot(x)=cot(x) ?
The answer to whether sin(x)sec(x)cot(x)=cot(x) is False