Is (cot^2(t))/(cos(t))=cot(t)csc(t) ?

The answer to whether (cot^2(t))/(cos(t))=cot(t)csc(t) is True

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prove (cot^2(t))/(cos(t))=cot(t)csc(t)

prove

\frac{cot ^{2} ( t )}{cos ( t )} = cot (t) csc (t)

True

Solution steps

\frac{cot ^{2} ( t )}{cos ( t )} = cot (t) csc (t)

Manipulating left side

\frac{cot ^{2} ( t )}{cos ( t )}

Express with sin, cos

= \frac{cos ( t )}{sin ^{2} ( t )}

Manipulating right side

cot (t) csc (t)

Express with sin, cos

= \frac{cos ( t )}{sin ^{2} ( t )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{sin ( x ) + tan ( x )}{1 + sec ( x )} = sec (x)

- csc^{2} (x) = - 1 - (cot (x))^{2}

\frac{1}{sin ^{2} ( x ) tan ( x )} = - sec (x)

\frac{1}{csc ( θ )} = - cos (θ)

tan (x) = \frac{1 - cos ( 2 x )}{sin ( x )}

Is (cot^2(t))/(cos(t))=cot(t)csc(t) ?
The answer to whether (cot^2(t))/(cos(t))=cot(t)csc(t) is True