Is 1/(sin^2(x)tan(x))=-sec(x) ?

The answer to whether 1/(sin^2(x)tan(x))=-sec(x) is False

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prove 1/(sin^2(x)tan(x))=-sec(x)

prove

\frac{1}{sin ^{2} ( x ) tan ( x )} = - sec (x)

False

Solution steps

\frac{1}{sin ^{2} ( x ) tan ( x )} = - sec (x)

Show that the two sides are not equal

For

\frac{1}{sin ^{2} ( x ) tan ( x )} = - sec (x)

plug in

x = 1

\frac{1}{sin ^{2} ( 1 ) tan ( 1 )} = 0.90681 \dots

\frac{1}{sin ^{2} ( 1 ) tan ( 1 )}

Refine to a decimal form

= 0.90681 \dots

- sec (1) = - 1.85081 \dots

- sec (1)

Refine to a decimal form

= - 1.85081 \dots

The two sides are not equal

\Rightarrow False

\frac{1}{csc ( θ )} = - cos (θ)

tan (x) = \frac{1 - cos ( 2 x )}{sin ( x )}

sin (\frac{π}{6} + x) + cos (\frac{π}{3} + x) = cos (x)

1 + tan^{2} (θ) = \frac{1}{cos ( θ )}

cot^{2} (x) = - 1 + csc^{2} (x)

Is 1/(sin^2(x)tan(x))=-sec(x) ?
The answer to whether 1/(sin^2(x)tan(x))=-sec(x) is False