Is tan(pi/3)sin((2pi)/3)=1+sin(pi/6) ?

The answer to whether tan(pi/3)sin((2pi)/3)=1+sin(pi/6) is True

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prove tan(pi/3)sin((2pi)/3)=1+sin(pi/6)

prove

tan (\frac{π}{3}) sin (\frac{2 π}{3}) = 1 + sin (\frac{π}{6})

True

Solution steps

tan (\frac{π}{3}) sin (\frac{2 π}{3}) = 1 + sin (\frac{π}{6})

Manipulating left side

tan (\frac{π}{3}) sin (\frac{2 π}{3})

Simplify

sin (\frac{2 π}{3}) tan (\frac{π}{3}) : \frac{3}{2}

= \frac{3}{2}

Manipulating right side

1 + sin (\frac{π}{6})

Simplify

1 + sin (\frac{π}{6}) : \frac{3}{2}

= \frac{3}{2}

We showed that the two sides could take the same form

\Rightarrow True

2 cot (x) + cos (x) - sec (x) = cot (x)

(tan (θ) + cot (θ)) sin (θ) cos (θ) = 1

3 (tan (x)) + 12 = 3

2 cos (x) tan (x) cot (x) = 2

sin (θ) = 0.2

Is tan(pi/3)sin((2pi)/3)=1+sin(pi/6) ?
The answer to whether tan(pi/3)sin((2pi)/3)=1+sin(pi/6) is True