Is tan^2(θ)+cot^2(θ)=sec^2(θ)csc^2(θ) ?

The answer to whether tan^2(θ)+cot^2(θ)=sec^2(θ)csc^2(θ) is False

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prove tan^2(θ)+cot^2(θ)=sec^2(θ)csc^2(θ)

prove

tan^{2} (θ) + cot^{2} (θ) = sec^{2} (θ) csc^{2} (θ)

False

Solution steps

tan^{2} (θ) + cot^{2} (θ) = sec^{2} (θ) csc^{2} (θ)

Show that the two sides are not equal

\Rightarrow False

cos^{2} (u) = 1 - sin^{2} (u)

sin^{2} (csc^{2} (x) - 1) = cos^{2} (x)

sin^{2} (x) - sin^{4} (x) = 1 - 2 sin^{2} (x)

\frac{1}{2} sin (2 x) = sin (x) cos (x)

\frac{4 - cos ( 2 x )}{8} = sin^{2} (x) cos^{2} (x)

Is tan^2(θ)+cot^2(θ)=sec^2(θ)csc^2(θ) ?
The answer to whether tan^2(θ)+cot^2(θ)=sec^2(θ)csc^2(θ) is False