Is (4-cos(2x))/8 =sin^2(x)cos^2(x) ?

The answer to whether (4-cos(2x))/8 =sin^2(x)cos^2(x) is False

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prove (4-cos(2x))/8 =sin^2(x)cos^2(x)

prove

\frac{4 - cos ( 2 x )}{8} = sin^{2} (x) cos^{2} (x)

False

Solution steps

\frac{4 - cos ( 2 x )}{8} = sin^{2} (x) cos^{2} (x)

Show that the two sides are not equal

\Rightarrow False

3 sin (x) = cos (x) cot (x)

1 = \frac{sec ( θ ) cot ( θ )}{csc ( θ )} - cot^{2} (θ)

(sec (α) + csc (α)) (cos (α) - sin (α)) = cot (α) - tan (α)

\frac{tan ^{2} ( θ )}{sec ^{2} ( θ )} = (1)

1 - (- cos (x))^{2} = 1 + cos^{2} (x)

Is (4-cos(2x))/8 =sin^2(x)cos^2(x) ?
The answer to whether (4-cos(2x))/8 =sin^2(x)cos^2(x) is False