Is 2sin(x)=((4cos(x)-1))/(tan(x)) ?

The answer to whether 2sin(x)=((4cos(x)-1))/(tan(x)) is False

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prove 2sin(x)=((4cos(x)-1))/(tan(x))

prove

2 sin (x) = \frac{( 4 cos ( x ) - 1 )}{tan ( x )}

False

Solution steps

2 sin (x) = \frac{4 cos ( x ) - 1}{tan ( x )}

Show that the two sides are not equal

For

2 sin (x) = \frac{4 cos ( x ) - 1}{tan ( x )}

plug in

x = 1

2 sin (1) = 1.68294 \dots

2 sin (1)

Refine to a decimal form

= 1.68294 \dots

\frac{4 cos ( 1 ) - 1}{tan ( 1 )} = 0.74560 \dots

\frac{4 cos ( 1 ) - 1}{tan ( 1 )}

Refine to a decimal form

= 0.74560 \dots

The two sides are not equal

\Rightarrow False

\frac{( 1 - cos ( 4 x ) + sin ( 4 x ) )}{( 1 + cos ( 4 x ) + sin ( 4 x ) )} = 3 sin (2 x)

csc^{2} (sin^{2} (x) - 1) = \frac{1}{cos ^{2} ( x )}

3 tan^{2} (y) (csc^{2} (y) - 1) = 3

tan (θ^{2}) + 6 = sec (θ^{2}) + 5

sec^{2} (θ) = (sec^{2} (θ) - 1) \cdot csc^{2} (θ)

Is 2sin(x)=((4cos(x)-1))/(tan(x)) ?
The answer to whether 2sin(x)=((4cos(x)-1))/(tan(x)) is False