Is sin(3θ)=3sin(θ)-4sin(3θ) ?

The answer to whether sin(3θ)=3sin(θ)-4sin(3θ) is False

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prove sin(3θ)=3sin(θ)-4sin(3θ)

prove

sin (3 θ) = 3 sin (θ) - 4 sin (3 θ)

False

Solution steps

sin (3 θ) = 3 sin (θ) - 4 sin (3 θ)

Show that the two sides are not equal

For

sin (3 θ) = 3 sin (θ) - 4 sin (3 θ)

plug in

θ = 1

sin (3 \cdot 1) = 0.14112 \dots

sin (3 \cdot 1)

Refine to a decimal form

= 0.14112 \dots

3 sin (1) - 4 sin (3 \cdot 1) = 1.95993 \dots

3 sin (1) - 4 sin (3 \cdot 1)

Refine to a decimal form

= 1.95993 \dots

The two sides are not equal

\Rightarrow False

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cos (- \frac{1}{2}) = cos (\frac{2}{2})

(\frac{1}{2} sin^{2} (θ)) = (\frac{1}{2} cos (2 θ))

(sin (3 x) + cos (3 x))^{2} = 1 + sin (6 x)

sin (x - π) = sin (x) - sin (π)

Is sin(3θ)=3sin(θ)-4sin(3θ) ?
The answer to whether sin(3θ)=3sin(θ)-4sin(3θ) is False