Is cos(-2x)=cosh^2(x)+sinh^2(x) ?

The answer to whether cos(-2x)=cosh^2(x)+sinh^2(x) is False

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prove cos(-2x)=cosh^2(x)+sinh^2(x)

prove

cos (- 2 x) = cosh^{2} (x) + sinh^{2} (x)

False

Solution steps

cos (- 2 x) = cosh^{2} (x) + sinh^{2} (x)

Show that the two sides are not equal

\Rightarrow False

(cos^{2} (x) + sin^{2} (x)) = 1

sec^{2} (a) = \frac{1}{1 - sin ^{2} ( a )}

sec (2 x) + tan (2 x) = \frac{( cos ( x ) + sin ( x ) )}{( cos ( x ) - sin ( x ) )}

\frac{sec ( - 1 )}{1 - cos ( x )} = sec (x)

cos^{2} (0) - sin^{2} (0) = 1 + sin (0)

Is cos(-2x)=cosh^2(x)+sinh^2(x) ?
The answer to whether cos(-2x)=cosh^2(x)+sinh^2(x) is False