Is tan^2(x)=2sin^2(x)-1 ?

The answer to whether tan^2(x)=2sin^2(x)-1 is False

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prove tan^2(x)=2sin^2(x)-1

prove

tan^{2} (x) = 2 sin^{2} (x) - 1

False

Solution steps

tan^{2} (x) = 2 sin^{2} (x) - 1

Show that the two sides are not equal

\Rightarrow False

tan (- \frac{π}{2} - θ) = cot (θ)

\frac{( 1 + tan ( θ ) )}{( 1 + cot ( θ ) )} = tan (θ)

\frac{1}{sin ^{2} ( θ )} = 1 - tan^{2} (θ)

\frac{1}{( sec ( θ ) ) ^{2}} + \frac{1}{( csc ( θ ) ) ^{2}} = 1

sin^{2} (\frac{a}{2}) = \frac{1 - cos ( a )}{2}