Is csc(2x)= 1/(sin^2(x)-1) ?

The answer to whether csc(2x)= 1/(sin^2(x)-1) is False

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prove csc(2x)= 1/(sin^2(x)-1)

prove

csc (2 x) = \frac{1}{sin ^{2} ( x ) - 1}

False

Solution steps

csc (2 x) = \frac{1}{sin ^{2} ( x ) - 1}

Show that the two sides are not equal

\Rightarrow False

(1 + tan^{2} (α)) (1 - sin^{2} (α)) = 1

csc (θ) - cot (θ) = \frac{1 - cos ( θ )}{sin ( θ )}

tan (x) = tan (x) + 2 sin^{2} (x)

\frac{1}{2 cot ( 1 - cos ^{2} ( x ) )} = csc (2 x)

2 cos (3 x) cos (3 x) = 1 - 2 sin (3 x) sin (2 x)

Is csc(2x)= 1/(sin^2(x)-1) ?
The answer to whether csc(2x)= 1/(sin^2(x)-1) is False