Is sec(b)cot(b)=csc(b)tan(b) ?

The answer to whether sec(b)cot(b)=csc(b)tan(b) is False

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prove sec(b)cot(b)=csc(b)tan(b)

prove

sec (b) cot (b) = csc (b) tan (b)

False

Solution steps

sec (b) cot (b) = csc (b) tan (b)

Show that the two sides are not equal

For

sec (b) cot (b) = csc (b) tan (b)

plug in

b = 1

sec (1) cot (1) = 1.18839 \dots

sec (1) cot (1)

Refine to a decimal form

= 1.18839 \dots

csc (1) tan (1) = 1.85081 \dots

csc (1) tan (1)

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

\frac{1 - sec ( x )}{csc ( x )} = cos (x) (cot (x))

cos (π θ) = - cos (θ)

csc (x) tan (x) sec (x) = sec^{2} (x)

tan (x) sec^{4} (x) = \frac{sin ( x )}{cos ^{5} ( x )}

csc (x) + cot (x) sec (x) - 1 = tan (x)

Is sec(b)cot(b)=csc(b)tan(b) ?
The answer to whether sec(b)cot(b)=csc(b)tan(b) is False