Is tan(x)+cot(x)*tan(x)=sec^2(x) ?

The answer to whether tan(x)+cot(x)*tan(x)=sec^2(x) is False

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prove tan(x)+cot(x)*tan(x)=sec^2(x)

prove

tan (x) + cot (x) \cdot tan (x) = sec^{2} (x)

False

Solution steps

tan (x) + cot (x) tan (x) = sec^{2} (x)

Show that the two sides are not equal

For

tan (x) + cot (x) tan (x) = sec^{2} (x)

plug in

x = 1

tan (1) + cot (1) tan (1) = 2.55740 \dots

tan (1) + cot (1) tan (1)

Refine to a decimal form

= 2.55740 \dots

sec^{2} (1) = 3.42551 \dots

sec^{2} (1)

Refine to a decimal form

= 3.42551 \dots

The two sides are not equal

\Rightarrow False

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5 cos^{2} (x) - 2 cos (x) - 3 - sin^{2} (x) = 0

sin (x) cos (\frac{π}{6}) - cos (x) sin (\frac{π}{6}) = sin (x - \frac{π}{6})

cos^{4} (a) + 1 - sin^{4} (a) = 2 cos^{2} (a)

3 - 4 cos^{2} (x) = (2 sin (x) + 1) (2 sin (x) - 1)

Is tan(x)+cot(x)*tan(x)=sec^2(x) ?
The answer to whether tan(x)+cot(x)*tan(x)=sec^2(x) is False