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Popular >

3sin(2x)>0

Solution

3 sin (2 x) > 0

Solution

πn < x < \frac{π}{2} + πn

+2

Interval Notation

(πn, \frac{π}{2} + πn)

Decimal Notation

πn < x < 1.57079 \dots + πn

Solution steps

3 sin (2 x) > 0

Divide both sides by

3

3 sin (2 x) > 0

Divide both sides by

3

\frac{3 sin ( 2 x )}{3} > \frac{0}{3}

Simplify

sin (2 x) > 0

sin (2 x) > 0

For

sin (x) > a

, if

- 1 \leq a < 1

then

arcsin (a) + 2 πn < x < π - arcsin (a) + 2 πn

arcsin (0) + 2 πn < 2 x < π - arcsin (0) + 2 πn

If

a < u < b

then

a < u and u < b

arcsin (0) + 2 πn < 2 x and 2 x < π - arcsin (0) + 2 πn

arcsin (0) + 2 πn < 2 x : x > πn

arcsin (0) + 2 πn < 2 x

Switch sides

2 x > arcsin (0) + 2 πn

Simplify

arcsin (0) + 2 πn : 2 πn

arcsin (0) + 2 πn

Use the following trivial identity:

arcsin (0) = 0

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= 0 + 2 πn

0 + 2 πn = 2 πn

= 2 πn

2 x > 2 πn

Divide both sides by

2

2 x > 2 πn

Divide both sides by

2

\frac{2 x}{2} > \frac{2 πn}{2}

Simplify

x > πn

x > πn

2 x < π - arcsin (0) + 2 πn : x < \frac{π}{2} + πn

2 x < π - arcsin (0) + 2 πn

Simplify

π - arcsin (0) + 2 πn : π + 2 πn

π - arcsin (0) + 2 πn

Use the following trivial identity:

arcsin (0) = 0

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= π - 0 + 2 πn

π - 0 + 2 πn = π + 2 πn

= π + 2 πn

2 x < π + 2 πn

Divide both sides by

2

2 x < π + 2 πn

Divide both sides by

2

\frac{2 x}{2} < \frac{π}{2} + \frac{2 πn}{2}

Simplify

x < \frac{π}{2} + πn

x < \frac{π}{2} + πn

Combine the intervals

x > πn and x < \frac{π}{2} + πn

Merge Overlapping Intervals

πn < x < \frac{π}{2} + πn

Popular Examples

cos(x)-sin(x)>=-3/2

cos (x) - sin (x) \geq - \frac{3}{2}

sin(θ)<= sqrt(3)cos(θ)

sin (θ) \leq 3 cos (θ)

tan(x/2-pi/3)>= 0

tan (\frac{x}{2} - \frac{π}{3}) \geq 0

tan(t)-tan^2(2)+sec^3(t)>0

tan (t) - tan^{2} (2) + sec^{3} (t) > 0

(2sin^2(2x)-1/2)<= 1/2

(2 sin^{2} (2 x) - \frac{1}{2}) \leq \frac{1}{2}