What is the value of ln(sec(pi/2)+tan(pi/2)) ?

The value of ln(sec(pi/2)+tan(pi/2)) is Undefined

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ln(sec(pi/2)+tan(pi/2))

ln (sec (\frac{π}{2}) + tan (\frac{π}{2}))

Undefined

Solution steps

ln (sec (\frac{π}{2}) + tan (\frac{π}{2}))

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{sin ( \frac{π}{2} )}{cos ( \frac{π}{2} )}

Simplify

\frac{sin ( \frac{π}{2} )}{cos ( \frac{π}{2} )} :

Undefined

\frac{sin ( \frac{π}{2} )}{cos ( \frac{π}{2} )}

cos (\frac{π}{2}) = 0

= \frac{sin ( \frac{π}{2} )}{0}

\frac{x}{0}

is undefined

= Undefined

= Undefined

9 cot^{2} (6 0^{\circ}) + sec (6 0^{\circ})

sin^{2} (8)

sin (6 7^{\circ}) (\frac{1}{2})^{\circ}

2 sin (18 0^{\circ}) + 3 cos (27 0^{\circ}) + 4 tan (36 0^{\circ})

cos^{2} (0.5)

What is the value of ln(sec(pi/2)+tan(pi/2)) ?
The value of ln(sec(pi/2)+tan(pi/2)) is Undefined