What is the value of 2sin(180)+3cos(270)+4tan(360) ?

The value of 2sin(180)+3cos(270)+4tan(360) is 0

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2sin(180)+3cos(270)+4tan(360)

2 sin (18 0^{\circ}) + 3 cos (27 0^{\circ}) + 4 tan (36 0^{\circ})

0

Solution steps

2 sin (18 0^{\circ}) + 3 cos (27 0^{\circ}) + 4 tan (36 0^{\circ})

Use the following trivial identity:

sin (18 0^{\circ}) = 0

Rewrite using trig identities:

cos (27 0^{\circ}) = 0

Rewrite using trig identities:

tan (36 0^{\circ}) = 0

= 2 \cdot 0 + 3 \cdot 0 + 4 \cdot 0

Simplify

= 0

cos^{2} (0.5)

arccos (\frac{1}{42})

arcsin (cos (\frac{43 π}{5}))

2 cos (\frac{π}{6}) + sin (\frac{5 π}{6}) - tan (\frac{π}{3})

e^{s i n (0)} cos^{2} (0) - e^{s i n (0)} sin (0)

What is the value of 2sin(180)+3cos(270)+4tan(360) ?
The value of 2sin(180)+3cos(270)+4tan(360) is 0