What is the value of sin(2pi)-sin((3pi)/2) ?

The value of sin(2pi)-sin((3pi)/2) is 1

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sin(2pi)-sin((3pi)/2)

sin (2 π) - sin (\frac{3 π}{2})

1

Solution steps

sin (2 π) - sin (\frac{3 π}{2})

sin (2 π) = sin (0)

= sin (0) - sin (\frac{3 π}{2})

Rewrite using trig identities:

- 2 sin (\frac{3 π}{4}) cos (\frac{3 π}{4})

= - 2 sin (\frac{3 π}{4}) cos (\frac{3 π}{4})

Use the following trivial identity:

sin (\frac{3 π}{4}) = \frac{2}{2}

Use the following trivial identity:

cos (\frac{3 π}{4}) = - \frac{2}{2}

= - 2 \cdot \frac{2}{2} (- \frac{2}{2})

Simplify

- 2 \cdot \frac{2}{2} (- \frac{2}{2}) : 1

= 1

12 sin (\frac{2 π}{3})

e cos (1) - e cos (2)

- 4 sin (12 (\frac{π}{8})) - 3 cos (12 (\frac{π}{8}))

- 3 sin (\frac{3 π}{4})

100 tan (3 0^{\circ})

What is the value of sin(2pi)-sin((3pi)/2) ?
The value of sin(2pi)-sin((3pi)/2) is 1