sec(-153)

Solution

sec (- 15 3^{\circ})

- \frac{2 ( - 10 - 2 5 + 4 ) ( 3 - 5 ) 2 5 - 5 + 4}{4}

Solution steps

sec (- 15 3^{\circ})

Use the following property:

sec (- x) = sec (x)

sec (- 15 3^{\circ}) = sec (15 3^{\circ})

= sec (15 3^{\circ})

Rewrite using trig identities:

\frac{1}{cos ( 15 3 ^{\circ} )}

= \frac{1}{cos ( 15 3 ^{\circ} )}

Rewrite using trig identities:

cos (15 3^{\circ}) = - \frac{2 4 + 2 5 - 5}{4}

= \frac{1}{- \frac{2 4 + 2 5 - 5}{4}}

Simplify

\frac{1}{- \frac{2 4 + 2 5 - 5}{4}} : - \frac{2 ( - 10 - 2 5 + 4 ) ( 3 - 5 ) 2 5 - 5 + 4}{4}

= - \frac{2 ( - 10 - 2 5 + 4 ) ( 3 - 5 ) 2 5 - 5 + 4}{4}

\frac{sin ^{2} ( - π )}{sec ^{2} ( - π ) - 1}

tanh (\frac{π}{4})

ln tan (\frac{π}{3}) + sec (\frac{π}{3})

2 sin (\frac{3 π}{5}) cos (\frac{3 π}{5})

sin (7.6)